X^2+(y+8)^2=2^2

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Solution for X^2+(y+8)^2=2^2 equation: 



X^2+(X+8)^2=2^2

We move all terms to the left:

X^2+(X+8)^2-(2^2)=0

We add all the numbers together, and all the variables

X^2+(X+8)^2-4=0

We move all terms containing X to the left, all other terms to the right

X^2+(X+8)^2=4

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